A battery is connected between two points A a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the lengths of the two arcs be $l_1 = r	heta$ and $l_2 = r(2\pi - 	heta)$.Since the ring is uniform,the resistances are $R_1 = ho \frac{l_

Vedclass · Accepted Answer

Zero for all values of $	heta$

Vedclass · Answer

(D) Let the lengths of the two arcs be $l_1 = r	heta$ and $l_2 = r(2\pi - 	heta)$.Since the ring is uniform,the resistances are $R_1 = ho \frac{l_1}{A}$ and $R_2 = ho \frac{l_2}{A}$.When connected to a battery,the potential difference $V$ across both arcs is the same. Thus,$i_1 R_1 = i_2 R_2$,which implies $i_1 l_1 = i_2 l_2$.The magnetic field at the center due to an arc of length $l$ carrying current $i$ is $B = \frac{\mu_0 i}{4\pi r^2} l$.For the two arcs,$B_1 = \frac{\mu_0 i_1 l_1}{4\pi r^2}$ and $B_2 = \frac{\mu_0 i_2 l_2}{4\pi r^2}$.Since $i_1 l_1 = i_2 l_2$,we have $B_1 = B_2$.The currents flow in opposite directions around the center,so the magnetic fields produced by the two arcs are equal in magnitude and opposite in direction.Therefore,the resultant magnetic induction at the center is $B_{net} = B_1 - B_2 = 0$,which is independent of $	heta$.

$A$ battery is connected between two points $A$ and $B$ on the circumference of a uniform conducting ring of radius $r$ and resistance $R$. One of the arcs $AB$ of the ring subtends an angle $\theta$ at the centre. The value of the magnetic induction at the centre due to the current in the ring is

Similar Questions

An electron moves along a vertical line and away from the observer. What is the pattern of the concentric circular magnetic field lines produced due to its motion?

Two identical coils having the same number of turns and carrying equal current have a common centre,and their planes are at right angles to each other. What is the ratio of the magnitude of the resultant magnetic field at the centre to the magnetic field due to one of the coils at the centre?

Biot-Savart law indicates that the moving electrons (velocity $\vec{v}$) produce a magnetic field $\vec{B}$ such that

$A$ coil having $N$ turns is wound tightly in the form of a spiral with inner and outer radii $a$ and $b$ respectively. Find the magnetic field at the centre,when a current $I$ passes through the coil.

Vedclass Test Series

Exam Paper Generator

Online Exam Module