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Question

(A) The bulk modulus $B$ is given by the formula $B = \frac{\Delta p}{\Delta V/V}$.Here,the change in pressure $\Delta p$ at depth $h$ is given by $\D

Vedclass · Accepted Answer

$19.6 	imes 10^8 \ N/m^2$

Vedclass · Answer

(A) The bulk modulus $B$ is given by the formula $B = \frac{\Delta p}{\Delta V/V}$.Here,the change in pressure $\Delta p$ at depth $h$ is given by $\Delta p = h ho g$.Given: $h = 200 \ m$,$ho = 10^3 \ kg/m^3$ (density of water),$g = 9.8 \ m/s^2$,and $\frac{\Delta V}{V} = 0.1\% = \frac{0.1}{100} = 10^{-3}$.Substituting the values:$B = \frac{200 	imes 10^3 	imes 9.8}{10^{-3}}$$B = \frac{19.6 	imes 10^5}{10^{-3}}$$B = 19.6 	imes 10^8 \ N/m^2$.

$A$ ball falling in a lake of depth $200 \ m$ shows $0.1\%$ decrease in its volume at the bottom. What is the bulk modulus of the material of the ball?

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$A$ ball is taken to a depth of $200 \ m$ in a lake. The decrease in its volume is $0.1\%$. Calculate the bulk modulus of the material of the ball.

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