A bag contains $8$ black and $7$ white balls. Two balls are drawn at random. Then for which the probability is more

  • A

    Both balls are white

  • B

    One ball is white and one is black

  • C

    Both balls are black

  • D

    All of the above are equals

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There are $3$ bags $A, B$ & $C$. Bag $A$ contains $1$ Red & $2$ Green balls, bag $B$ contains $2$ Red & $1$ Green balls and bag $C$ contains only one green ball. One ball is drawn from bag $A$ & put into bag $B$ then one ball is drawn from $B$ & put into bag $C$ & finally one ball is drawn from bag $C$ & put into bag $A$. When this operation is completed, probability that bag $A$ contains $2$ Red & $1$ Green balls, is -

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