$A$ bag contains $3$ white and $2$ black balls and another bag contains $2$ white and $4$ black balls. $A$ bag is chosen at random and a ball is picked up from it. The probability of the ball being black is:

One bag contains $5$ white and $4$ black balls. Another bag contains $7$ white and $9$ black balls. $A$ ball is transferred from the first bag to the second and then a ball is drawn from the second. The probability that the ball drawn is white,is

$A$ bag contains $16$ coins,of which $2$ are counterfeit with heads on both sides. The rest are fair coins. One coin is selected at random from the bag and tossed. The probability of getting a head is

There are $3$ bags $A, B$ and $C$. Bag $A$ contains $2$ white and $3$ black balls,bag $B$ contains $4$ white and $2$ black balls and Bag $C$ contains $3$ white and $2$ black balls. If a ball is drawn at random from a randomly chosen bag,then the probability that the ball drawn is black,is

Two coins and one die are tossed. What is the probability of getting heads on both coins and $3$ or $6$ on the die?

The chance of India winning the toss is $3/4$. If it wins the toss,then its chance of victory is $4/5$,otherwise it is only $1/2$. Then the chance of India's victory is: