A bag contains 3 black and 4 white balls. Two | vedclass

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Question

(c) Second white ball can draw in two ways.

$(i)$ First is white and second is white

Probability $ = \frac{4}{7} 	imes \frac{3}{6} = \frac{2}{7

Vedclass · Accepted Answer

$\frac{4}{7}$

Vedclass · Answer

(c) Second white ball can draw in two ways.

$(i)$ First is white and second is white

Probability $ = \frac{4}{7} 	imes \frac{3}{6} = \frac{2}{7}$

$(ii)$ First is black and second is white

Probability $ = \frac{3}{7} 	imes \frac{4}{6} = \frac{2}{7}$

Hence required probability $ = \frac{2}{7} + \frac{2}{7} = \frac{4}{7}.$

A bag contains $3$ black and $4$ white balls. Two balls are drawn one by one at random without replacement. The probability that the second drawn ball is white, is

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