A bag contains 4 white,5 black,and 6 red ball | vedclass

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(D) Total number of balls in the bag $= 4 + 5 + 6 = 15$.Number of white balls $= 4$.Number of red balls $= 6$.Since the events of drawing a white ball

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$\frac{2}{3}$

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(D) Total number of balls in the bag $= 4 + 5 + 6 = 15$.Number of white balls $= 4$.Number of red balls $= 6$.Since the events of drawing a white ball and a red ball are mutually exclusive,the probability of drawing either a white or a red ball is the sum of their individual probabilities.Probability of drawing a white ball $P(W) = \frac{4}{15}$.Probability of drawing a red ball $P(R) = \frac{6}{15}$.Probability (white or red) $= P(W) + P(R) = \frac{4}{15} + \frac{6}{15} = \frac{10}{15} = \frac{2}{3}$.

$A$ bag contains $4$ white,$5$ black,and $6$ red balls. If a ball is drawn at random,what is the probability that the drawn ball is either white or red?

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