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(D) Let the number of $10$-paise coins be $17k$ and the number of $25$-paise coins be $6k$.The total value of $10$-paise coins is $17k 	imes 0.10 = 1

Vedclass · Accepted Answer

$595$

Vedclass · Answer

(D) Let the number of $10$-paise coins be $17k$ and the number of $25$-paise coins be $6k$.The total value of $10$-paise coins is $17k 	imes 0.10 = 1.7k$ rupees.The total value of $25$-paise coins is $6k 	imes 0.25 = 1.5k$ rupees.Given that the total money is $Rs. 112$,we have:$1.7k + 1.5k = 112$$3.2k = 112$$k = \frac{112}{3.2} = 35$Therefore,the number of $10$-paise coins is $17 	imes 35 = 595$.

$A$ bag contains $10$-paise and $25$-paise coins in the ratio of $17:6$. If the total money in the bag is $Rs. 112$,the number of $10$-paise coins is:

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