If 3 A = 6 B = 9 C,what is A : B : C? | vedclass

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(B) Given the equation $3 A = 6 B = 9 C$.Let $3 A = 6 B = 9 C = x$.Then,$A = \frac{x}{3}$,$B = \frac{x}{6}$,and $C = \frac{x}{9}$.To find the ratio $A

Vedclass · Accepted Answer

$6 : 3 : 2$

Vedclass · Answer

(B) Given the equation $3 A = 6 B = 9 C$.Let $3 A = 6 B = 9 C = x$.Then,$A = \frac{x}{3}$,$B = \frac{x}{6}$,and $C = \frac{x}{9}$.To find the ratio $A : B : C$,we write:$A : B : C = \frac{x}{3} : \frac{x}{6} : \frac{x}{9}$.To simplify this,we find the Least Common Multiple $(LCM)$ of the denominators $3, 6,$ and $9$,which is $18$.Multiplying each term by $18$:$A : B : C = (\frac{x}{3} 	imes 18) : (\frac{x}{6} 	imes 18) : (\frac{x}{9} 	imes 18)$.$A : B : C = 6x : 3x : 2x$.Removing the common variable $x$,we get $A : B : C = 6 : 3 : 2$.

If $3 A = 6 B = 9 C$,what is $A : B : C$?

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