A bag contains $9$ discs of which $4$ are red, $3$ are blue and $2$ are yellow. The discs are similar in shape and size. A disc is drawn at random from the bag. Calculate the probability that it will be blue

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There are $9$ discs in all so the total number of possible outcomes is $9 .$

Let the events $A, \,B, \,C$ be defined as

$A:$ 'the disc drawn is red'

$B:$ 'the disc drawn is yellow'

$C:$ 'the disc drawn is blue'.

The number of blue discs $=3,$ i.e., $n(C)=3$

Therefore, $P(C)=\frac{3}{9}=\frac{1}{3}$

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