A G.P. consists of an even number of terms. I | vedclass

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Question

(c) Let there be $2n$ terms in the given $G.P.$ with first term $a$ and the common ratio $r$.

Then, $a\frac{{({r^{2n}} - 1)}}{{(r - 1)}} = 5a\frac{

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(c) Let there be $2n$ terms in the given $G.P.$ with first term $a$ and the common ratio $r$.

Then, $a\frac{{({r^{2n}} - 1)}}{{(r - 1)}} = 5a\frac{{({r^{2n}} - 1)}}{{({r^2} - 1)}}$

$ \Rightarrow $$r + 1 = 5$

$ \Rightarrow $$r = 4$.

A $G.P.$ consists of an even number of terms. If the sum of all the terms is $5$ times the sum of the terms occupying odd places, then the common ratio will be equal to

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