A $100$ watt electric bulb is lighted for $2$ hours daily. and four $40$ watt bulbs are lighted for $4$ hours everyday. Calculate the energy consumed (in $k W h$ ) in $30$ days.
Energy consumed by $100$ watt bulb working for $2$ hours
$=\frac{100}{1000} kW \times 2$ hour $=0.2 kW h$
Energy consumed by four $40$ watt bulbs working everyday for $4$ hours
$=\frac{40 \times 4 \times 4}{1000} kWh =0.64 kW h$
Total energy consumed everyday
$=(0.20+0.64) kW h =0.84 kW h$
Total energy consumed in $30$ days
$=0.84 kW h \times 30=25.2 kW h$
Why are alloys commonly used in electrical heating devices ?
How much current will an electric bulb of resistance $1100\, \Omega$ draw from a $220\, V$ source $?$ If $a$ heater of resistance $100\, \Omega$ is connected to the same source instead of the bulb, calculate the current drawn by the heater.
$(a)$ Derive the formula for the calculation of work done when current flows through a resistor
$(b)$ One electric bulb is rated $40\, W$ and $240\, V$ and other $25\, W$ and $240\, V$. Which bulb has higher resistance and how many times ?
$(a)$ What are the values of $mA$ and $\mu A$ ?
$(b)$ Draw the symbols of battery and rheostat.
A bulb is rated at $5.0\, V , 100 \,mA$. Calculate its
$(i)$ power and $(ii)$ resistance.