A TV transmission tower has a height of 140, | vedclass

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(A) The maximum distance $d$ for $LOS$ communication is given by the formula: $d = \sqrt{2R h_T} + \sqrt{2R h_R}$.Given:Height of transmitter tower $h

Vedclass · Accepted Answer

$65$

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(A) The maximum distance $d$ for $LOS$ communication is given by the formula: $d = \sqrt{2R h_T} + \sqrt{2R h_R}$.Given:Height of transmitter tower $h_T = 140\, m$Height of receiving antenna $h_R = 40\, m$Radius of Earth $R = 6.4 	imes 10^6\, m$Substituting the values:$d = \sqrt{2 	imes 6.4 	imes 10^6 	imes 140} + \sqrt{2 	imes 6.4 	imes 10^6 	imes 40}$$d = \sqrt{1792 	imes 10^6} + \sqrt{512 	imes 10^6}$$d = (42.33 	imes 10^3) + (22.63 	imes 10^3)$$d = 64.96 	imes 10^3\, m \approx 65\, km$.

$A$ $TV$ transmission tower has a height of $140\, m$ and the height of the receiving antenna is $40\, m$. What is the maximum distance up to which signals can be broadcasted from this tower in $LOS$ (Line of Sight) mode? (Given: radius of earth $R = 6.4 \times 10^6\, m$)

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