$A$ $100\, W$ bulb $B_1$ and two $60\, W$ bulbs $B_2$ and $B_3$ are connected to a $220\, V$ source,as shown in the figure. If $P_1, P_2$,and $P_3$ are the output powers of the bulbs $B_1, B_2$,and $B_3$ respectively,then:

  • A
    $P_1 > P_2 = P_3$
  • B
    $P_1 > P_2 > P_3$
  • C
    $P_1 < P_2 = P_3$
  • D
    $P_1 < P_2 < P_3$

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