$A$ heating coil is labelled $100\, W$,$220\, V$. The coil is cut in half and the two pieces are joined in parallel to the same source. The energy now liberated per second is .............. $J/s$.

  • A
    $200$
  • B
    $400$
  • C
    $25$
  • D
    $50$

Explore More

Similar Questions

The current flowing in the given circuit is $0.1\,A$. The potential difference between the points $X$ and $Y$ is ................ $V$.

An electric current is passed through a circuit containing two wires of the same material,connected in parallel. If the lengths and radii of the wires are in the ratio of $4/3$ and $2/3$ respectively,then the ratio of the currents passing through the wires will be:

The magnitude of $i$ in ampere unit is

Difficult
View Solution

If each resistor in the given figure is $9\, \Omega$,then the reading of the ammeter is .............. $A$.

Difficult
View Solution

In the circuit shown,the current through the $4\,\Omega$ resistor is $1\,A$ when the points $P$ and $M$ are connected to a d.c. voltage source. The potential difference between the points $M$ and $N$ is ............... $V$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo