A (100, W,200, V) bulb is connected to a 160, | vedclass

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Question

(A) The resistance $R$ of the bulb is calculated using its rated power $P_R$ and rated voltage $V_R$:$R = \frac{V_R^2}{P_R} = \frac{200^2}{100} = \fra

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$64$

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(A) The resistance $R$ of the bulb is calculated using its rated power $P_R$ and rated voltage $V_R$:$R = \frac{V_R^2}{P_R} = \frac{200^2}{100} = \frac{40000}{100} = 400\,\Omega$.When connected to a supply voltage $V = 160\, V$,the power consumed $P$ is given by:$P = \frac{V^2}{R} = \frac{160^2}{400} = \frac{25600}{400} = 64\, W$.Alternatively,using the ratio formula:$P_{consumed} = \left( \frac{V}{V_R} ight)^2 	imes P_R = \left( \frac{160}{200} ight)^2 	imes 100 = (0.8)^2 	imes 100 = 0.64 	imes 100 = 64\, W$.

$A$ ($100\, W$,$200\, V$) bulb is connected to a $160\, V$ power supply. The power consumption would be ............. $W$.

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