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(D) The rate at which chemical energy is consumed is equal to the total power dissipated in the circuit,which includes both the external resistance an

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$1$

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(D) The rate at which chemical energy is consumed is equal to the total power dissipated in the circuit,which includes both the external resistance and the internal resistance of the cell.Total resistance $R_{total} = R_{external} + r_{internal} = 21\,\Omega + 4\,\Omega = 25\,\Omega$.The current $I = 0.2\,A$.The rate of energy consumption (power) is given by $P = I^2 	imes R_{total}$.$P = (0.2)^2 	imes 25 = 0.04 	imes 25 = 1\,J/s$.Therefore,the correct option is $D$.

The internal resistance of a primary cell is $4\,\Omega$. It generates a current of $0.2\,A$ in an external resistance of $21\,\Omega$. The rate at which chemical energy is consumed in providing the current is .............. $J/s$.

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