Y xleftarrow[(ii),KOD, Br_2, Delta]{(i),NH_3, | vedclass

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(A) The reaction is the Hofmann bromamide degradation,where the amide nitrogen is retained in the amine product.$1$. For $X$: Benzoic acid reacts with

Vedclass · Accepted Answer

$X$ is $	ext{deuterated aniline} (C_6H_5ND_2)$; $Y$ is $	ext{aniline} (C_6H_5NH_2)$

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(A) The reaction is the Hofmann bromamide degradation,where the amide nitrogen is retained in the amine product.$1$. For $X$: Benzoic acid reacts with $ND_3$ and $\Delta$ to form benzamide $(C_6H_5COND_2)$. Subsequent reaction with $KOH$ and $Br_2$ yields $C_6H_5ND_2$ $(X)$,as the nitrogen atom of the amide is retained in the amine.$2$. For $Y$: Benzoic acid reacts with $NH_3$ and $\Delta$ to form benzamide $(C_6H_5CONH_2)$. Subsequent reaction with $KOD$ and $Br_2$ yields $C_6H_5NH_2$ $(Y)$,as the nitrogen atom of the amide is retained in the amine.Thus,$X$ is $C_6H_5ND_2$ and $Y$ is $C_6H_5NH_2$.

$Y \xleftarrow[(ii)\,KOD, Br_2, \Delta]{(i)\,NH_3, \Delta} \text{Benzoic acid}$ $\xrightarrow[(ii)\,KOH, Br_2, \Delta]{(i)\,ND_3, \Delta} X$
What are $X$ and $Y$?

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$Y \xleftarrow[(ii)\,KOD, Br_2, \Delta]{(i)\,NH_3, \Delta} \text{Benzoic acid}$ $\xrightarrow[(ii)\,KOH, Br_2, \Delta]{(i)\,ND_3, \Delta} X$What are $X$ and $Y$?