Which of the following is least basic?

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Question

(C) The basicity of an amine depends on the availability of the lone pair of electrons on the nitrogen atom for protonation.$1$. In $(CH_3CO)\ddot{N}H

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$(CH_3CO)_2\ddot{N}H$

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(C) The basicity of an amine depends on the availability of the lone pair of electrons on the nitrogen atom for protonation.$1$. In $(CH_3CO)\ddot{N}HC_2H_5$ (an amide),the lone pair on nitrogen is delocalized due to conjugation with the carbonyl group $(C=O)$,making it less available.$2$. In $(C_2H_5)_3\ddot{N}$ (a tertiary amine),the lone pair is localized and available for donation.$3$. In $(CH_3CO)_2\ddot{N}H$ (an imide),the lone pair on nitrogen is strongly delocalized due to conjugation with two electron-withdrawing carbonyl groups. This makes the lone pair least available for protonation,rendering it the least basic.$4$. In $(C_2H_5)_2\ddot{N}H$ (a secondary amine),the lone pair is localized and available for donation.Therefore,$(CH_3CO)_2\ddot{N}H$ is the least basic compound.

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