1-Propanol can be prepared from propene by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The preparation of $1-$propanol from propene is achieved via hydroboration-oxidation.Reaction: $CH_3-CH=CH_2$ $\xrightarrow{B_2H_6, THF} (CH_3-CH_

Vedclass · Accepted Answer

$B_2H_6 - THF$ and $H_2O_2/OH^{-}$

Vedclass · Answer

(C) The preparation of $1-$propanol from propene is achieved via hydroboration-oxidation.Reaction: $CH_3-CH=CH_2$ $\xrightarrow{B_2H_6, THF} (CH_3-CH_2-CH_2)_3B$ $\xrightarrow{H_2O_2, OH^{-}} 3 CH_3-CH_2-CH_2OH$.Option $A$ $(H_2O/H^{\oplus})$ follows Markovnikov's rule,yielding propan$-2-$ol.Option $B$ ($Hg(OAc)_2/H_2O$ and $NaBH_4$) is oxymercuration-demercuration,which also follows Markovnikov's rule,yielding propan$-2-$ol.Option $C$ ($B_2H_6 - THF$ and $H_2O_2/OH^{-}$) is hydroboration-oxidation,which follows anti-Markovnikov's rule,yielding $1-$propanol.Therefore,option $C$ is correct.

$1-$Propanol can be prepared from propene by

Similar Questions

The reaction of $CH_3-CH=CH_2$ (propene) with $HI$ gives isopropyl iodide instead of $n$-propyl iodide because:

$C_8H_{16}$ that can form cis-trans geometrical isomers and also has a chiral centre,is

The reaction of propene with $HOCl$ proceeds via the addition of

The reaction of $3$-phenylpropene with $HBr$ gives (as the major product):

What is the first step of the addition reaction when $HBr$ is added to propene in the absence of peroxide?

Vedclass Test Series

Exam Paper Generator

Online Exam Module