C_4H_9Cl (Optically Active Compound A) xright | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of an alkyl halide with $NaCN$ in $DMSO$ proceeds via an $S_N2$ mechanism. In an $S_N2$ reaction,there is an inversion of configurati

Vedclass · Accepted Answer

Vedclass · Answer

(A) The reaction of an alkyl halide with $NaCN$ in $DMSO$ proceeds via an $S_N2$ mechanism. In an $S_N2$ reaction,there is an inversion of configuration (Walden inversion) at the chiral center. The product formed is $(R)-2-$methylbutanenitrile. Since the reaction involves inversion of configuration,the starting material (compound $A$) must have the $(S)$ configuration. The structure of $2-$methylbutanenitrile is $CH_3-CH(CH_3)-CH_2-CN$. Therefore,the starting material $A$ is $(S)-2-$chlorobutane,which is $CH_3-CH(Cl)-CH_2-CH_3$. Among the given options,the structure corresponding to $(S)-2-$chlorobutane is represented by option $A$.

$C_4H_9Cl$ (Optically Active Compound $A$) $\xrightarrow[DMSO]{NaCN}$ $(R)-2-$methylbutanenitrile; Identify compound $A$?

Similar Questions

The formation of alkene from alkyl halide is an example of

Which of the following has the shortest $C-Cl$ bond?

Which of the following alkyl halides is the fastest to undergo dehydrohalogenation with a base?

Chloroethane with silver acetate forms $X$ and with $LiAlH_4$ forms $Y$. What are $X$ and $Y$?

Among the bromides $(I)-(III)$ given below,the order of reactivity for ${S_N}^1$ reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module