Among the bromides (I)-(III) given below,the | vedclass

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(A) The reactivity of ${S_N}^1$ reaction depends on the stability of the carbocation intermediate formed after the departure of the leaving group $(Br

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$III > II > I$

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(A) The reactivity of ${S_N}^1$ reaction depends on the stability of the carbocation intermediate formed after the departure of the leaving group $(Br^-)$.$1$. For $(I)$,the carbocation formed is a cyclopentenyl cation,which is stabilized by resonance with one double bond.$2$. For $(II)$,the carbocation formed is a cyclopentadienyl cation,which is aromatic ($6 \pi$ electrons,Huckel's rule).$3$. For $(III)$,the carbocation formed is stabilized by resonance with two double bonds and the lone pair of the oxygen atom,making it highly stable due to the $+M$ effect of the oxygen atom.Comparing the stabilities:- The carbocation from $(III)$ is the most stable due to the $+M$ effect of the oxygen atom.- The carbocation from $(II)$ is aromatic and very stable.- The carbocation from $(I)$ is the least stable among the three as it has the least resonance stabilization.Therefore,the order of reactivity is $III > II > I$.

Among the bromides $(I)-(III)$ given below,the order of reactivity for ${S_N}^1$ reaction is:

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