$\int_{\frac{\pi}{4}}^{\frac{\pi}{4}} \log_e(\sin x + \cos x) \, dx$ is equal to

  • A
    $-\frac{\pi}{4} \ln 2$
  • B
    $\frac{\pi}{4} \ln 2$
  • C
    $\frac{\pi}{8} \ln 2$
  • D
    $0$

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Similar Questions

For $0 < x < \frac{\pi}{2}$,the integral $\int_{\frac{1}{2}}^{\frac{\sqrt{3}}{2}} \ln(e^{\cos x}) \, d(\sin x)$ is equal to:

Let $I_{1}=\int_{0}^{n}[x] d x$ and $I_{2}=\int_{0}^{n}\{x\} d x,$ where $[x]$ and $\{x\}$ are the integral and fractional parts of $x$ respectively,and $n \in N-\{1\}.$ Then,$I_{1} / I_{2}$ is equal to

$ \int_{0}^{\frac{\pi}{2}} \frac{dx}{1+\cos x} = $

If $\int_0^b \frac{dx}{1+x^2} = \int_b^{\infty} \frac{dx}{1+x^2}$,then $b$ is equal to

$\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \sin^2 x \, dx = $ . . . . . . .

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