$2\ kg$ ice at $-20^o\ C$ is mixed with $5\ kg$ water at $20^o\ C$. Then final amount of water in the mixture would be ; Given specific heat of ice $= 0.5\ cal/g^o\ C$, specific heat of water $= 1\ cal/g^o\ C$, Latent heat of fusion of ice $= 80\ cal/g$ ........ $kg$
$2\ kg$ ice at $-20^o\ C$ is mixed with $5\ kg$ water at $20^o\ C$. Then final amount of water in the mixture would be ; Given specific heat of ice $= 0.5\ cal/g^o\ C$, specific heat of water $= 1\ cal/g^o\ C$, Latent heat of fusion of ice $= 80\ cal/g$ ........ $kg$
- A
$6$
- B
$5$
- C
$4$
- D
$2$
Similar Questions
$200 \,g$ of ice at $-20^{\circ} C$ is mixed with $500 \,g$ of water at $20^{\circ} C$ in an insulating vessel. Final mass of water in vessel is ........... $g$ (specific heat of ice $=0.5 \,cal g ^{-10} C ^{-1}$ )
$200 \,g$ of ice at $-20^{\circ} C$ is mixed with $500 \,g$ of water at $20^{\circ} C$ in an insulating vessel. Final mass of water in vessel is ........... $g$ (specific heat of ice $=0.5 \,cal g ^{-10} C ^{-1}$ )
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A 'thermacole' icebox is a cheap and an efficient method for storing small quantities of cooked food in summer in particular. A cubical icebox of side $30 \,cm$ has a thickness of $5.0\; cm .$ If $4.0\; kg$ of ice is put in the box, estimate the amount of ice (in $kg$) remaining after $6 \;h$. The outside temperature is $45\,^{\circ} C ,$ and co-efficient of thermal conductivity of thermacole is $0.01\; J s ^{-1} m ^{-1} K ^{-1} .$ Heat of fuston of water $=335 \times 10^{3}\;J kg ^{-1} $
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A $2\,kg$ copper block is heated to $500^o\,C$ and then it is placed on a large block of ice at $0^o\,C$. If the specific heat capacity of copper is $400\, J/kg/ ^o\,C$ and latent heat of fusion of water is $3.5 \times 10^5\, J/kg$, the amount of ice, that can melt is :-
A $2\,kg$ copper block is heated to $500^o\,C$ and then it is placed on a large block of ice at $0^o\,C$. If the specific heat capacity of copper is $400\, J/kg/ ^o\,C$ and latent heat of fusion of water is $3.5 \times 10^5\, J/kg$, the amount of ice, that can melt is :-
Heat is being supplied at a constant rate to a sphere of ice which is melting at the rate of $0.1 \,\,gm/sec$. It melts completely in $100\,\,sec$. The rate of rise of temperature thereafter will be ........$^oC/\sec$ (Assume no loss of heat.)
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