$A$ particle of mass $3m$ is projected from the ground at some angle with the horizontal. The horizontal range is $R$. At the highest point of its path,it breaks into two pieces of mass $m$ and $2m$. The smaller mass comes to rest,and the larger mass finally falls at a distance $x$ from the point of projection. The value of $x$ is:

  • A
    $\frac{3R}{4}$
  • B
    $\frac{3R}{2}$
  • C
    $\frac{5R}{4}$
  • D
    $3R$

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