A capacitor C = 2 mu F and an inductor with L | vedclass

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(C) The average power $P$ in an $AC$ circuit is given by the formula:$P = V_{rms} I_{rms} \cos \phi$Since $V_{rms} = I_{rms} Z$ and the power factor $

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$20$

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(C) The average power $P$ in an $AC$ circuit is given by the formula:$P = V_{rms} I_{rms} \cos \phi$Since $V_{rms} = I_{rms} Z$ and the power factor $\cos \phi = \frac{R}{Z}$,where $Z$ is the impedance of the circuit and $R$ is the resistance.Substituting these into the power formula:$P = (I_{rms} Z) 	imes I_{rms} 	imes \left( \frac{R}{Z} ight)$$P = I_{rms}^2 R$Given that $I_{rms} = 2 A$ and $R = 5 \Omega$:$P = (2)^2 	imes 5$$P = 4 	imes 5 = 20 \, W$Therefore,the average power in the circuit is $20 \, W$.

$A$ capacitor $C = 2 \mu F$ and an inductor with $L = 10 H$ and coil resistance $R = 5 \Omega$ are connected in series in a circuit. When an alternating current of $r.m.s.$ value $I_{rms} = 2 A$ flows in the circuit,the average power in watts in the circuit is:

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