A particle is moving in uniform circular moti | vedclass

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(A) The angular momentum $L$ of a particle is defined as $L = r 	imes p$. The rate of change of angular momentum is equal to the torque applied,given

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About the center of the circle

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(A) The angular momentum $L$ of a particle is defined as $L = r 	imes p$. The rate of change of angular momentum is equal to the torque applied,given by $\frac{dL}{dt} = 	au = r 	imes F$.In uniform circular motion,the centripetal force $F$ always acts towards the center of the circle.Since the position vector $r$ is measured from the center,the force $F$ passes through the center,making the lever arm zero.Therefore,the torque $	au = r 	imes F = 0$ about the center of the circle.Since $	au = 0$,the angular momentum $L$ remains constant (conserved) about the center of the circle.

$A$ particle is moving in uniform circular motion. About which point in the plane of the circle will the angular momentum of the particle always remain conserved?

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