If the rotational kinetic energy of a body is $10 \ J$,and its angular momentum vector coincides with the axis of rotation,and its moment of inertia about this axis is $8 \times 10^{-7} \ kg \ m^2$,then the angular momentum of the body will be:

Define angular momentum.

$A$ particle of mass $2\, kg$ is on a smooth horizontal table and moves in a circular path of radius $0.6\, m$. The height of the table from the ground is $0.8\, m$. If the angular speed of the particle is $12\, rad\, s^{-1}$,the magnitude of its angular momentum about a point on the ground right under the centre of the circle is ........ $kg\, m^2\, s^{-1}$.

$A$ particle of mass $m$ moves along a straight line $AB$ in the $XY$ plane. Let $L_A$ and $L_B$ be the angular momentum of the particle about the origin $O$ when it is at points $A$ and $B$ respectively. Then:

The units of angular momentum are

Angular momentum is