$_{86}{A^{222}}{ \to _{84}}{B^{210}}$. In this reaction how many $\alpha $ and $\beta $ particles are emitted

Originally the radioactive beta decay was thought as a decay of a nucleus with the emission of electrons only (Case $I$) . However, in addition to the electron, another (nearly) massless and electrically neutral particle is also emitted (Case $II$). Based on the figure below, which of the following is correct?

A radioactive nucleus $_{92}{X^{235}}$decays to $_{91}{Y^{231}}$. Which of the following particles are emitted

The mass of a nucleus ${ }_Z^A X$ is less that the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m_1$ and $m_2$ only if $\left(m_1+m_2\right)M^{\prime}$. The masses of some neutral atoms are given in the table below:

$1.$ The correct statement is:

$(A)$ The nucleus ${ }_3^6 Li$ can emit an alpha particle

$(B)$ The nucleus ${ }_{84}^{210} P_0$ can emit a proton

$(C)$ Deuteron and alpha particle can undergo complete fusion.

$(D)$ The nuclei ${ }_{30}^{70} Zn$ and ${ }_{34}^{82} Se$ can undergo complete fusion.

$2.$ The kinetic energy (in $keV$ ) of the alpha particle, when the nucleus ${ }_{84}^{210} P _0$ at rest undergoes alpha decay, is:

$(A)$ $5319$ $(B)$ $5422$ $(C)$ $5707$ $(D)$ $5818$

Give the answer question $1$ and $2.$

What happens to the mass number and atomic number of an element when it emits $\gamma$-radiation?

In the nuclear decay given below 

$_z{X^A}{ \to _{z + 1}}{Y^A}{ \to _{z - 1}}{K^{A - 4}}{ \to _{z - 1}}{K^{A - 4}}$

the particles emitted in the sequence are