Let R be a transitive relation on a set A and | vedclass

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(D) By definition,the identity relation $I$ on a set $A$ is defined as $I = \{(a, a) : a \in A\}$.Since $R$ is a transitive relation on $A$,it does no

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None of these

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(D) By definition,the identity relation $I$ on a set $A$ is defined as $I = \{(a, a) : a \in A\}$.Since $R$ is a transitive relation on $A$,it does not necessarily imply that $R$ must contain $I$ or be contained within $I$.For example,if $A = \{1, 2\}$,let $R = \{(1, 1), (2, 2), (1, 2)\}$. Here,$R$ is transitive and $I = \{(1, 1), (2, 2)\}$. In this case,$I \subset R$.However,if $R = \{(1, 1)\}$,$R$ is transitive,but $I 
ot\subset R$ and $R 
ot\subset I$.Since no specific condition (like reflexivity or symmetry) is given for $R$ other than transitivity,none of the options $R \subset I$,$I \subset R$,or $R = I$ are universally true.Therefore,the correct answer is $D$.

Let $R$ be a transitive relation on a set $A$ and $I$ be the identity relation on $A$. Then:

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