If $R$ is a relation from set $A$ to set $B$,then

Given $A = \{1, 2, 3, 4, 5\}$ and $B = \{1, 4, 5\}$. If $R$ is a relation from $A$ to $B$ such that $(x, y) \in R$ with $x > y$,then the range of $R$ is:

Let $A = \{1, 2, 3, 4\}$,$B = \{1, 5, 9, 11, 15, 16\}$,and $f = \{(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)\}$. Is $f$ a relation from $A$ to $B$? Justify your answer.

Let $A = \{1, 2, 3\}$ and $B = \{1, 3, 5\}$. If a relation $R$ from $A$ to $B$ is defined as $R = \{(1, 3), (2, 5), (3, 3)\}$,then find the inverse relation ${R^{ - 1}}$.

Let $R$ be a relation from $N$ to $N$ defined by $R = \{(a, b) : a, b \in N \text{ and } a = b^2\}$. Is the following statement true?
$(a, b) \in R$ implies $(b, a) \in R$

Let the number of elements of the sets $A$ and $B$ be $p$ and $q$,respectively. Then,the number of relations from the set $A$ to the set $B$ is