C and Si both have the same lattice structure | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of carbon $(^{6}C)$ is $1s^{2} 2s^{2} 2p^{2}$.The electronic configuration of silicon $(_{14}Si)$ is $1s^{2} 2s^{2} 2

Vedclass · Accepted Answer

The four bonding electrons in the case of $C$ lie in the second orbit,whereas in the case of $Si$ they lie in the third.

Vedclass · Answer

(C) The electronic configuration of carbon $(^{6}C)$ is $1s^{2} 2s^{2} 2p^{2}$.The electronic configuration of silicon $(_{14}Si)$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{2}$.In $C$,the valence electrons are in the $n=2$ shell,which is closer to the nucleus,resulting in a large energy band gap $(E_{g} \approx 5.4 \ eV)$,making it an insulator.In $Si$,the valence electrons are in the $n=3$ shell,which is further from the nucleus,resulting in a smaller energy band gap $(E_{g} \approx 1.1 \ eV)$,allowing it to act as an intrinsic semiconductor.Therefore,the four bonding electrons of $C$ and $Si$ lie in the second and third orbits,respectively.

$C$ and $Si$ both have the same lattice structure,having $4$ bonding electrons in each. However,$C$ is an insulator whereas $Si$ is an intrinsic semiconductor. This is because:

Similar Questions

In semiconductors at room temperature,

Which of the energy band diagrams shown in the figure corresponds to that of a semiconductor?

The energy gap in case of which of the following is less than $ 3 eV $?

State the value of the energy band gap difference between the valence band $(E_V)$ and the conduction band $(E_C)$ for $C$ (Diamond), $Si$, and $Ge$.

The energy band diagrams for three semiconductor samples of silicon are as shown. We can then assert that

Vedclass Test Series

Exam Paper Generator

Online Exam Module