$_1H^1 + _1H^1 + _1H^2 \to X + _{+1}e^0 + \text{energy}$. The emitted particle $X$ is:

If the binding energy per nucleon of deuteron $({ }_1 H^2)$ is $1.15 \text{ MeV}$ and an $\alpha$-particle has a binding energy of $7.1 \text{ MeV}$ per nucleon,then the energy released per nucleon in the given reaction is ${ }_1 H^2 + { }_1 H^2 \rightarrow { }_2 He^4 + Q$. (in $\text{ MeV}$)

Consider the nuclear fission $Ne^{20} \to 2He^4 + C^{12}$. Given that the binding energy per nucleon of $Ne^{20}$,$He^4$,and $C^{12}$ are,respectively,$8.03\, MeV$,$7.07\, MeV$,and $7.86\, MeV$,identify the correct statement.

Thermal neutrons are those which

$A$ nuclear fission process is given by $A^{240} \rightarrow B^{100} + C^{140} + Q$ (energy). If the binding energy per nucleon for nuclei $A, B,$ and $C$ are $7.6 \, MeV, 8.1 \, MeV,$ and $8.1 \, MeV$ respectively,then the energy $Q$ released is approximately $...... \, MeV$.

The number of neutrons released when $_{92}U^{235}$ undergoes fission by absorbing $_0n^1$ and $(_{56}Ba^{144} + _{36}Kr^{89})$ are formed,is