Benzoic acid on heating with X gives benzene | vedclass

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(D) Benzoic acid $(C_6H_5COOH)$ reacts with sodalime $(NaOH + CaO)$ to undergo decarboxylation,yielding benzene $(C_6H_6)$ and sodium carbonate $(Na_2

Vedclass · Accepted Answer

Sodalime and Zinc dust

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(D) Benzoic acid $(C_6H_5COOH)$ reacts with sodalime $(NaOH + CaO)$ to undergo decarboxylation,yielding benzene $(C_6H_6)$ and sodium carbonate $(Na_2CO_3)$. Thus,$X$ is sodalime.Phenol $(C_6H_5OH)$ reacts with zinc dust $(Zn)$ to undergo reduction,yielding benzene $(C_6H_6)$ and zinc oxide $(ZnO)$. Thus,$Y$ is zinc dust.Therefore,$X$ is sodalime and $Y$ is zinc dust. The correct option is $D$.

Benzoic acid on heating with $X$ gives benzene and phenol on heating with $Y$ gives benzene. What are $X$ and $Y$ respectively?

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