When phenol is treated with CHCl_3 and NaOH f | vedclass

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(D) The reaction described is the Reimer-Tiemann reaction. $1$. First,$CHCl_3$ reacts with $OH^-$ to generate the electrophile dichlorocarbene,$:CCl_2

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Both $(B)$ and $(C)$

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(D) The reaction described is the Reimer-Tiemann reaction. $1$. First,$CHCl_3$ reacts with $OH^-$ to generate the electrophile dichlorocarbene,$:CCl_2$. $2$. The phenoxide ion attacks the dichlorocarbene to form a cyclohexadienyl anion intermediate,which is represented by structure $(B)$. $3$. This intermediate undergoes a proton shift to form the ortho-dichloromethyl phenoxide ion,which is represented by structure $(C)$. $4$. Therefore,both $(B)$ and $(C)$ are intermediates involved in the mechanism of the Reimer-Tiemann reaction.

List-$I$	List-$II$
$A$. $H_{3}C-CH(OH)-CH_{3}$	$I$. $(i)$ oleum; (ii) $NaOH, \Delta$; (iii) $H^{+}$
$B$. $CH_{3}COOH \rightarrow CH_{3}CH_{2}OH$	$II$. $(i)$ $O_{2}$; (ii) $H_{2}O/H^{+}$
$C$. $CH_{3}CH_{2}OH \rightarrow H_{3}C-CH(OH)-CH_{3}$	$III$. $(i)$ $CH_{3}OH, H^{+}$; (ii) $H_{2}$,Catalyst
$D$. Benzene $\rightarrow$ Phenol	$IV$. $(i)$ conc. $H_{2}SO_{4}, \Delta$; (ii) $H^{+}/H_{2}O$

When phenol is treated with $CHCl_3$ and $NaOH$ followed by acidification,salicylaldehyde is produced. Which of the following intermediates is involved in the above reaction?

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