$A$ capacitor is charged to $320\ V$ and then connected to a resistor. After $1\ s$,the voltage is $240\ V$. What will be the voltage after $2\ s$ and $3\ s$?

In the circuit shown in the figure,the switch $S$ is initially open and the capacitor is initially uncharged. $I_1, I_2$ and $I_3$ represent the current in the resistance $2\,\Omega, 8\,\Omega$ and $4\,\Omega$ respectively.

Assertion : $A$ capacitor blocks direct current in the steady state.
Reason : The capacitive reactance of the capacitor is inversely proportional to frequency $f$ of the source of $emf$.

$A$ capacitor of capacity $C$ is charged to a steady potential difference $V$ and connected in series with an open key and a pure resistor $R$. At time $t = 0$,the key is closed. If $I$ is the current at time $t$,a plot of $\log I$ against $t$ is as shown in $(1)$ in the graph. Later,one of the parameters,i.e.,$V, R,$ or $C$,is changed while keeping the other two constant,and the graph $(2)$ is recorded. Then:

In the circuit shown,the cells are ideal and of equal emfs $E$. The capacitance of the capacitor is $C$ and the resistance of the resistor is $R$. $X$ is first joined to $Y$ and then to $Z$. After a long time,the total heat produced in the resistor will be:

At time $t = 0$,the switch $K$ is closed. Which of the following statements is true for the current '$i$' flowing through the resistor $AB$ in the given circuit?