(A) The capacitive reactance $X_{C}$ is given by the formula $X_{C} = \frac{1}{2 \pi f C}$.For direct current $(DC)$,the frequency $f$ is $0$.Substitu

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(A) The capacitive reactance $X_{C}$ is given by the formula $X_{C} = \frac{1}{2 \pi f C}$.For direct current $(DC)$,the frequency $f$ is $0$.Substituting $f = 0$ into the formula,we get $X_{C} = \frac{1}{2 \pi (0) C} = \infty$.Since the capacitive reactance becomes infinite for $DC$,the capacitor offers infinite resistance to the flow of direct current,effectively blocking it in the steady state.Therefore,both the Assertion and the Reason are correct,and the Reason correctly explains why the capacitor blocks $DC$.Hence,option $A$ is correct.

Class 12 Physics Electric Potential and Capacitance Charging and Discharging of Capacitance and RC circuit (DC)

Easy

Assertion : $A$ capacitor blocks direct current in the steady state.
Reason : The capacitive reactance of the capacitor is inversely proportional to frequency $f$ of the source of $emf$.

AIIMS 2011 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Electric Potential and Capacitance

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Charging and Discharging of Capacitance and RC circuit (DC)

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AIIMS 2011 Paper All AIIMS years →

$A$ combination of two identical capacitors, a resistor $R$, and a $DC$ voltage source of voltage $6\; V$ is used in an experiment on a $C-R$ circuit. It is found that for a parallel combination of the capacitors, the time in which the voltage of the fully charged combination reduces to half its original voltage is $10\; s$. For a series combination, the time needed for reducing the voltage of the fully charged series combination by half is: (in $; s$)

DifficultAIEEE 2011

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At $t = 0$,switch $S$ is closed. The charge on the capacitor is varying with time $t$ as $Q = Q_0(1 - e^{-\alpha t})$. Find the value of $Q_0$.

Medium

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$A$ capacitor of capacitance $C$ is charged with the help of a $200 \,V$ battery. It is then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $2.5 \times 10^2 \,J/(kg \cdot K)$ and mass $0.1 \,kg$. If the temperature of the block rises by $0.4 \,K$,the value of $C$ is

Easy

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Given,
${R_1} = 1\,\Omega, R_2 = 2\,\Omega$
${C_1} = 2\,\mu F, C_2 = 4\,\mu F$
The time constants (in $\mu s$) for the circuits $I, II, III$ are respectively:

Difficult

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The circuit shown has been connected for a long time. The voltage across the capacitor is ............. $V$.

MediumKVPY 2013

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Assertion : $A$ capacitor blocks direct current in the steady state.Reason : The capacitive reactance of the capacitor is inversely proportional to frequency $f$ of the source of $emf$.

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At $t = 0$,switch $S$ is closed. The charge on the capacitor is varying with time $t$ as $Q = Q_0(1 - e^{-\alpha t})$. Find the value of $Q_0$.

Given,${R_1} = 1\,\Omega, R_2 = 2\,\Omega$${C_1} = 2\,\mu F, C_2 = 4\,\mu F$The time constants (in $\mu s$) for the circuits $I, II, III$ are respectively:

The circuit shown has been connected for a long time. The voltage across the capacitor is ............. $V$.

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Assertion : $A$ capacitor blocks direct current in the steady state.
Reason : The capacitive reactance of the capacitor is inversely proportional to frequency $f$ of the source of $emf$.

Given,
${R_1} = 1\,\Omega, R_2 = 2\,\Omega$
${C_1} = 2\,\mu F, C_2 = 4\,\mu F$
The time constants (in $\mu s$) for the circuits $I, II, III$ are respectively: