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(A) In a satellite,the effective gravity is zero $(g_{eff} = 0)$.Therefore,the only force acting between the two spheres is the electrostatic repulsiv

Vedclass · Accepted Answer

$180^\circ, \frac{1}{4\pi \varepsilon_0} \cdot \frac{Q^2}{(2L)^2}$

Vedclass · Answer

(A) In a satellite,the effective gravity is zero $(g_{eff} = 0)$.Therefore,the only force acting between the two spheres is the electrostatic repulsive force.Since both spheres have the same charge $+Q$,they will repel each other and move as far apart as possible.The strings will align in a straight line,making the angle between them $	heta = 180^\circ$.The distance between the two charges is $r = L + L = 2L$.The electrostatic force (which is equal to the tension $T$ in the strings) is given by Coulomb's law:$T = F = \frac{1}{4\pi \varepsilon_0} \cdot \frac{Q \cdot Q}{(2L)^2} = \frac{1}{4\pi \varepsilon_0} \cdot \frac{Q^2}{4L^2}$.

What is the angle between the strings and the tension in the strings when two spheres are suspended in a satellite as shown in the figure?

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