A square plate of side 0.1 , m moves over ano | vedclass

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(D) Given: Side of the square plate $L = 0.1 \, m$,Velocity $dv = 0.1 \, m/s$,Viscosity $\eta = 0.01 \, poise = 0.001 \, N \cdot s/m^2$ ($SI$ unit),Vi

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$0.0005$

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(D) Given: Side of the square plate $L = 0.1 \, m$,Velocity $dv = 0.1 \, m/s$,Viscosity $\eta = 0.01 \, poise = 0.001 \, N \cdot s/m^2$ ($SI$ unit),Viscous force $F = 0.002 \, N$.Area of the plate $A = L^2 = (0.1)^2 = 0.01 \, m^2$.According to Newton's law of viscosity,the viscous force is given by $F = \eta A \frac{dv}{dx}$,where $dx$ is the distance between the plates.Rearranging the formula for $dx$: $dx = \frac{\eta A dv}{F}$.Substituting the values: $dx = \frac{0.001 	imes 0.01 	imes 0.1}{0.002} = \frac{0.000001}{0.002} = 0.0005 \, m$.

$A$ square plate of side $0.1 \, m$ moves over another plate with a velocity of $0.1 \, m/s$ in a liquid of viscosity $0.01 \, poise$. If the viscous force acting is $0.002 \, N$,what is the distance between the two plates (in $, m$)?

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