A cubical block of side a and density rho sli | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Since the block moves with constant velocity,the net force acting on it is zero.The component of the gravitational force acting down the incline i

Vedclass · Accepted Answer

$\frac{ho agt \sin 	heta}{v}$

Vedclass · Answer

(A) Since the block moves with constant velocity,the net force acting on it is zero.The component of the gravitational force acting down the incline is $F = mg \sin 	heta$.Here,$m = ho V = ho a^3$,so $F = ho a^3 g \sin 	heta$.According to Newton's law of viscosity,the viscous force is $F = \eta A \left(\frac{dv}{dx}ight)$,where $A = a^2$ is the contact area and $\frac{dv}{dx} = \frac{v}{t}$ is the velocity gradient.Equating the forces: $ho a^3 g \sin 	heta = \eta a^2 \left(\frac{v}{t}ight)$.Solving for the coefficient of viscosity $\eta$: $\eta = \frac{ho a^3 g \sin 	heta \cdot t}{a^2 v} = \frac{ho agt \sin 	heta}{v}$.

$A$ cubical block of side $a$ and density $\rho$ slides over a fixed inclined plane with constant velocity $v$. There is a thin film of viscous fluid of thickness $t$ between the plane and the block. Then the coefficient of viscosity of the thin film will be

Similar Questions

The velocity of the upper layer of water in a river is $36 \, km/h$. The shearing stress between horizontal layers of water is $10^{-3} \, N/m^2$. The depth of the river is $h$. (The coefficient of viscosity of water is $10^{-2} \, Pa \cdot s$). Find the value of $h$ in meters.

What is the value of the shear modulus of sulfuric acid?

The viscous force between two liquid layers is

Discuss the coefficient of viscosity in terms of stress and strain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module