A body thrown on Earth reaches a height of 90 | vedclass

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(C) The acceleration due to gravity is given by $g = \frac{GM}{R^2}$.Comparing the gravity on the planet $(g_p)$ and Earth $(g_e)$:$\frac{g_p}{g_e} =

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$100$

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(C) The acceleration due to gravity is given by $g = \frac{GM}{R^2}$.Comparing the gravity on the planet $(g_p)$ and Earth $(g_e)$:$\frac{g_p}{g_e} = \frac{M_p}{M_e} 	imes \left( \frac{R_e}{R_p} ight)^2$Given $M_p = \frac{1}{10} M_e$ and $R_p = \frac{1}{3} R_e$:$\frac{g_p}{g_e} = \frac{1}{10} 	imes \left( \frac{3}{1} ight)^2 = \frac{9}{10}$.The maximum height reached is $H = \frac{u^2}{2g}$,which implies $H \propto \frac{1}{g}$.Therefore,$\frac{H_p}{H_e} = \frac{g_e}{g_p} = \frac{10}{9}$.$H_p = \frac{10}{9} 	imes H_e = \frac{10}{9} 	imes 90 = 100\,m$.

$A$ body thrown on Earth reaches a height of $90\,m$. If the same body is thrown on a planet with $\frac{1}{10}$ of the mass and $\frac{1}{3}$ of the radius of Earth,it will reach a height of ....... $m$.

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