If a ball can be thrown to a maximum horizont | vedclass

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(D) The maximum horizontal range $R_{\max}$ is given by the formula $R_{\max} = \frac{u^2}{g} = 80 \, m$,where $u$ is the initial velocity and $g$ is

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$40$

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(D) The maximum horizontal range $R_{\max}$ is given by the formula $R_{\max} = \frac{u^2}{g} = 80 \, m$,where $u$ is the initial velocity and $g$ is the acceleration due to gravity.The maximum height $H_{\max}$ reached when thrown vertically upwards is given by $H_{\max} = \frac{u^2}{2g}$.By substituting the value of $R_{\max}$ into the expression for $H_{\max}$,we get:$H_{\max} = \frac{1}{2} \left( \frac{u^2}{g} ight) = \frac{1}{2} 	imes 80 \, m = 40 \, m$.Therefore,the maximum height to which the ball can be thrown is $40 \, m$.

If a ball can be thrown to a maximum horizontal distance of $80 \, m$,what is the maximum height to which it can be thrown (in $, m$)?

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