Find the equation of a line that makes an int | vedclass

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(D) The slope of the line is $m = 	an(	heta) = 	an(	an^{-1}(\frac{3}{5})) = \frac{3}{5}$.Given the $y$-intercept $c = -3$.The slope-intercept form

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None of these

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(D) The slope of the line is $m = 	an(	heta) = 	an(	an^{-1}(\frac{3}{5})) = \frac{3}{5}$.Given the $y$-intercept $c = -3$.The slope-intercept form of a line is $y = mx + c$.Substituting the values,we get $y = \frac{3}{5}x - 3$.Multiplying by $5$,we get $5y = 3x - 15$.Rearranging the terms,we get $3x - 5y - 15 = 0$ or $5y - 3x + 15 = 0$ is not correct,let's re-evaluate.$5y = 3x - 15 \implies 3x - 5y - 15 = 0$.Checking the options,none of the provided equations match $3x - 5y - 15 = 0$ exactly.Therefore,the correct option is $D$.

Find the equation of a line that makes an intercept of $-3$ on the $y$-axis and makes an angle of ${\tan ^{ - 1}}\frac{3}{5}$ with the $x$-axis.

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