If the equation of a system of parallel chord | vedclass

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(D) The equation of the parabola is $y^2 = \frac{25}{7}x$. Comparing this with $y^2 = 4ax$,we get $4a = \frac{25}{7}$,so $a = \frac{25}{28}$.Given the

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$56y = 25$

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(D) The equation of the parabola is $y^2 = \frac{25}{7}x$. Comparing this with $y^2 = 4ax$,we get $4a = \frac{25}{7}$,so $a = \frac{25}{28}$.Given the system of parallel chords is $4x - y + \lambda = 0$,the slope of these chords is $m = 4$.The equation of the diameter of a parabola $y^2 = 4ax$ corresponding to chords of slope $m$ is given by $y = \frac{2a}{m}$.Substituting the values,$y = \frac{2 	imes (25/28)}{4} = \frac{50/28}{4} = \frac{50}{112} = \frac{25}{56}$.Thus,$56y = 25$.

If the equation of a system of parallel chords of the parabola $y^2 = \frac{25x}{7}$ is $4x - y + \lambda = 0$,then the equation of the corresponding diameter is . . . . . .

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