If x + 2y = 3 is a line and A(-1, 3),B(2, -3) | vedclass

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(C) Let the equation of the line be $f(x, y) = x + 2y - 3 = 0$.Substitute the coordinates of points $A, B,$ and $C$ into $f(x, y)$:For $A(-1, 3)$: $f(

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$A, C$ lie on one side of the line and $B$ lies on the other side.

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(C) Let the equation of the line be $f(x, y) = x + 2y - 3 = 0$.Substitute the coordinates of points $A, B,$ and $C$ into $f(x, y)$:For $A(-1, 3)$: $f(-1, 3) = -1 + 2(3) - 3 = -1 + 6 - 3 = 2 > 0$.For $B(2, -3)$: $f(2, -3) = 2 + 2(-3) - 3 = 2 - 6 - 3 = -7 For $C(4, 9)$: $f(4, 9) = 4 + 2(9) - 3 = 4 + 18 - 3 = 19 > 0$.Since $f(A)$ and $f(C)$ have the same sign (positive) and $f(B)$ has a different sign (negative),points $A$ and $C$ lie on one side of the line,while point $B$ lies on the other side.

If $x + 2y = 3$ is a line and $A(-1, 3)$,$B(2, -3)$,and $C(4, 9)$ are three points,then:

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