Find the equation of the bisector of the obtuse angle between the lines $3x - 4y + 7 = 0$ and $12x + 5y - 2 = 0$.

Let $'C'$ be the locus of the centre of circles which touch the lines $x + 2y - 5 = 0$ and $2x - 4y + 7 = 0$. If the area enclosed by the curve $'C'$ with the line $x - y - 5 = 0$ is $\frac{P^2}{2Q^2}$,where $P$ and $Q$ are relative primes,then the value of $P + Q$ is:

The equation of the perpendicular bisector of the line segment joining the points $(1, 2)$ and $(-2, 0)$ is:

The family of lines,forming an isosceles triangle with the lines $3x - 4y - 2 = 0$ and $12x - 5y + 6 = 0$,is

The equations of the angle bisectors between the lines $3x - 4y + 7 = 0$ and $12x - 5y - 8 = 0$ are:

Let $P(-1, 0)$,$Q(0, 0)$,and $R(3, 3\sqrt{3})$ be three points. The equation of the bisector of the angle $\angle PQR$ is: