Find the equation of the latus rectum of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given equation of the parabola is $x^2 = -12y$.Comparing this with the standard form $x^2 = -4ay$,we get $4a = 12$,which implies $a = 3$.The f

Vedclass · Accepted Answer

$y = -3$

Vedclass · Answer

(C) The given equation of the parabola is $x^2 = -12y$.Comparing this with the standard form $x^2 = -4ay$,we get $4a = 12$,which implies $a = 3$.The focus of this parabola is $(0, -a) = (0, -3)$.The latus rectum is a line passing through the focus and perpendicular to the axis of the parabola.Since the axis of the parabola is the $y$-axis,the latus rectum is a horizontal line given by $y = -a$.Therefore,the equation of the latus rectum is $y = -3$.

Find the equation of the latus rectum of the parabola $x^2 = -12y$.

Similar Questions

If the normal chord drawn at the point $\left(\frac{15}{2}, \frac{15}{\sqrt{2}}\right)$ to the parabola $y^2=15x$ subtends an angle $\theta$ at the vertex of the parabola,then $\sin \frac{\theta}{3}+\cos \frac{2\theta}{3}-\sec \frac{4\theta}{3}=$

The maximum number of common normals of $y^2=4ax$ and $x^2=4by$ is equal to

The equation of the tangent to the parabola $y^2 = 16x$,which is perpendicular to the line $y = 3x + 7$,is

The radius of the smallest circle which touches the parabolas $y = x^2 + 2$ and $x = y^2 + 2$ is

If the line $y = 2x + k$ is a tangent to the curve $x^2 = 4y$,then $k$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module