Let PS be the median of the triangle with ver | vedclass

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(D) The median $PS$ connects vertex $P$ to the midpoint $S$ of side $QR$.Midpoint $S = \left( \frac{6+7}{2}, \frac{-1+3}{2} \right) = \left( \frac{13}

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$2x + 9y + 7 = 0$

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(D) The median $PS$ connects vertex $P$ to the midpoint $S$ of side $QR$.Midpoint $S = \left( \frac{6+7}{2}, \frac{-1+3}{2} \right) = \left( \frac{13}{2}, 1 \right)$.The slope of $PS$ is $m = \frac{1 - 2}{\frac{13}{2} - 2} = \frac{-1}{\frac{9}{2}} = -\frac{2}{9}$.The line passing through $(1, -1)$ parallel to $PS$ has the same slope $m = -\frac{2}{9}$.Using the point-slope form: $y - (-1) = -\frac{2}{9}(x - 1)$.$9(y + 1) = -2(x - 1) \implies 9y + 9 = -2x + 2$.$2x + 9y + 7 = 0$.

Let $PS$ be the median of the triangle with vertices $P(2, 2)$,$Q(6, -1)$,and $R(7, 3)$. The equation of the line passing through $(1, -1)$ and parallel to $PS$ is:

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