What is the number of possible geometric isom | vedclass

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(A) The complex $[Pt(Py)(NH_3)BrCl]$ is a square planar complex of the type $[M(abcd)]$,where $M = Pt$,$a = Py$,$b = NH_3$,$c = Br$,and $d = Cl$.For a

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$3$

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(A) The complex $[Pt(Py)(NH_3)BrCl]$ is a square planar complex of the type $[M(abcd)]$,where $M = Pt$,$a = Py$,$b = NH_3$,$c = Br$,and $d = Cl$.For a square planar complex of the type $[M(abcd)]$,the number of geometric isomers is given by $3$.These isomers correspond to the arrangements where any one ligand is fixed,and the other three are arranged in different positions relative to it.Specifically,if we fix $Py$ at one position,the other three ligands $(NH_3, Br, Cl)$ can be placed in $3$ different ways relative to $Py$ (trans to $NH_3$,trans to $Br$,or trans to $Cl$).

What is the number of possible geometric isomers for the complex $[Pt(Py)(NH_3)BrCl]$?

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