The total number of possible isomers for squa | vedclass

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(B) The square planar complex is of the type $[Mabcd]^{n\pm}$,where $M = Pt^{2+}$,$a = Cl^-$,$b = NO_2^-$,$c = NO_3^-$,and $d = SCN^-$.For a square pl

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$12$

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(B) The square planar complex is of the type $[Mabcd]^{n\pm}$,where $M = Pt^{2+}$,$a = Cl^-$,$b = NO_2^-$,$c = NO_3^-$,and $d = SCN^-$.For a square planar complex $[Mabcd]$,there are $3$ geometrical isomers.In this complex,$NO_2^-$ and $SCN^-$ are ambidentate ligands.An ambidentate ligand can coordinate through two different donor atoms.Since there are $2$ ambidentate ligands,each geometrical isomer can exist in $2 	imes 2 = 4$ linkage isomeric forms.Therefore,the total number of isomers = (Number of geometrical isomers) $	imes$ (Number of linkage isomers per geometrical isomer) = $3 	imes 4 = 12$.

The total number of possible isomers for square planar $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}$ is:

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