For a t_{2g}^6 e_g^2 system,the value of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic moment is calculated using the formula $\mu = \sqrt{n(n + 2)}$,where $n$ is the number of unpaired electrons.In the $t_{2g}^6 e_g^2$

Vedclass · Accepted Answer

$2.83$

Vedclass · Answer

(A) The magnetic moment is calculated using the formula $\mu = \sqrt{n(n + 2)}$,where $n$ is the number of unpaired electrons.In the $t_{2g}^6 e_g^2$ configuration,the $t_{2g}$ orbitals are fully filled ($6$ electrons),and the $e_g$ orbitals contain $2$ electrons.According to Hund's rule,the $2$ electrons in the $e_g$ orbitals will remain unpaired.Therefore,the number of unpaired electrons $n = 2$.Substituting the value of $n$ into the formula: $\mu = \sqrt{2(2 + 2)} = \sqrt{8} \approx 2.83 \ B.M.$

For a $t_{2g}^6 e_g^2$ system,the value of the magnetic moment $(\mu)$ is equal to ..... $B.M.$

Similar Questions

Which of the following ion/ions is/are diamagnetic?

The type of isomerism between $[Co(en)_2(NCS)_2]Cl$ and $[Co(en)_2(NCS)Cl]NCS$ is ............ .

Which among the following is most paramagnetic?

The species with spin only magnetic moment of $\sqrt{24} \, BM$ is

Which of the following complexes will show both geometrical and optical isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module